\u00a0ch\u00ednh x\u00e1c nh\u1ea5t<\/span><\/p><\/blockquote>\nQu\u00e1 tr\u00ecnh soi c\u1ea7u 2888 mi\u1ec1n B\u1eafc<\/strong>\u00a0theo ph\u01b0\u01a1ng ph\u00e1p n\u00e0y c\u0169ng kh\u00f4ng qu\u00e1 kh\u00f3 kh\u0103n. Anh em ch\u1ec9 c\u1ea7n quan t\u00e2m \u0111\u1ebfn gi\u1ea3i \u0111\u1eb7c bi\u1ec7t v\u00e0 gi\u1ea3i s\u1ed1 7. Khi c\u00f3 k\u1ebft qu\u1ea3, l\u1ea5y s\u1ed1 \u0111\u1ea7u v\u00e0 s\u1ed1 cu\u1ed1i c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t c\u1ed9ng t\u1ed5ng l\u1ea1i v\u1edbi nhau. N\u1ebfu \u0111\u00e1p \u00e1n l\u1edbn h\u01a1n 10 th\u00ec c\u1ed9ng ti\u1ebfp sao cho ra m\u1ed9t ch\u1eef s\u1ed1; t\u1ed5ng v\u1ec1 10 th\u00ec ch\u1ecdn k\u1ebft qu\u1ea3 l\u00e0 0; nh\u1ecf h\u01a1n 10 th\u00ec ch\u1ecdn gi\u1eef ngay s\u1ed1 \u0111\u00f3. Ti\u1ebfp \u0111\u00f3, ta s\u1ebd l\u1ea5y b\u00f3ng c\u1ee7a t\u1ed5ng \u0111\u00f3 \u0111\u1ec3 cho ra m\u1ed9t s\u1ed1 g\u1ecdi l\u00e0 s\u1ed1 X.<\/span><\/p>\nTrong gi\u1ea3i 7 th\u01b0\u1eddng ta s\u1ebd th\u1ea5y c\u00f3 t\u1ed5ng 4 gi\u1ea3i, t\u01b0\u01a1ng \u1ee9ng v\u1edbi 8 s\u1ed1. Trong 8 s\u1ed1 \u0111\u00f3, ch\u1ecdn ra 2 s\u1ed1 th\u01b0\u1eddng xuy\u00ean xu\u1ea5t hi\u1ec7n nhi\u1ec1u nh\u1ea5t r\u1ed3i \u0111\u1eb7t l\u00e0 A, B. C\u00f2n trong tr\u01b0\u1eddng h\u1ee3p 2 s\u1ed1 c\u00f3 t\u1ea7n s\u1ed1 xu\u1ea5t hi\u1ec7n ngang nhau. Khi \u0111\u00f3 ta s\u1ebd \u01b0u ti\u00ean s\u1ed1 n\u1eb1m \u1edf v\u1ecb tr\u00ed b\u00ean tr\u00e1i, sau \u0111\u00f3 m\u1edbi \u0111\u1ebfn b\u00ean ph\u1ea3i. T\u1eeb 3 s\u1ed1 X – A – B, ta s\u1ebd c\u00f3 c\u00e1c c\u1eb7p XA v\u00e0 XB, \u0111\u00e2y s\u1ebd l\u00e0 nh\u1eefng s\u1ed1 m\u00e0 ta d\u00f9ng \u0111\u1ec3 \u0111\u00e1nh l\u00f4 trong 3 ng\u00e0y t\u1edbi. N\u1ebfu b\u1ea1n th\u1ea5y l\u00f4 v\u1ec1 th\u00ec ph\u1ea3i b\u1ecf ngay \u0111\u1ec3 \u0111\u00e1nh s\u1ed1 kh\u00e1c. C\u00f2n kh\u00f4ng v\u1ec1 th\u00ec c\u0169ng ph\u1ea3i b\u1ecf \u0111\u1ec3 thay th\u1ebf b\u1eb1ng s\u1ed1 m\u1edbi \u0111\u1ec3 \u0111\u1ea3m b\u1ea3o kh\u00f4ng b\u1ecb l\u1ed7 qu\u00e1 nhi\u1ec1u.<\/span><\/p>\n